shivam01 said:
helps me in getting familiar to CAUCHY”S
Inequalities are generally present in CAT and similar MBA papers, the question can be direct or indirect.
AM-GM Inequality
It means that AM( arithemetic mean) of a set of positive numbers is always greater than or equal to the GM( geometric mean). The equality holds when the numbers are equal
Example 1: If a,b,c are positive numbers prove that 
what we will do is use AM-GM multiple times

similarly for others

then multiplying these three inequalities we get the desired result!
Practice Problem 1: show that ![(n^n)[(n+1)/2]^{(2n)}>(n!)^3 (n^n)[(n+1)/2]^{(2n)}>(n!)^3](http://learnhub.com/images/equations/52d15a69696385fe8d8ca5885c6045c1c9522823.png)
Practice Problem 2: if x,y,z be the lengths of the sides of a triangle then prove that 
Practice Problem 3: show that for any natural number 
Example 2: Show that for any natural number ![n 2^n>=1 +n.2^{[(n-1)/2]} n 2^n>=1 +n.2^{[(n-1)/2]}](http://learnhub.com/images/equations/01f65c6969f8fa6029f36abfaccc80b1a983b752.png)
Lets see how we do this![2^n>=1+n.2^{[(n-1)/2]} 2^n>=1+n.2^{[(n-1)/2]}](http://learnhub.com/images/equations/4de99205cd03a987f99566419766441208d78035.png)
( can you recognise the form?)
its the sum of a GP
we need to use AM-GM on the sum of GP![[1+2+2^2\cdots +2^{(n-1)}]/n>(1.2.2^2\cdots 2^{(n-1)})^{(1/n)} [1+2+2^2\cdots +2^{(n-1)}]/n>(1.2.2^2\cdots 2^{(n-1)})^{(1/n)}](http://learnhub.com/images/equations/750dafcd7a0fd900ebb517303eede73f3f55a6b4.png)
![(2^{n-1})/n> ( 2^{(1+2+3\cdots +n-1)})^{(1/n)}=(2^{[n(n-1)/2]})^{(1/n)}=2^{((n-1)/2)} (2^{n-1})/n> ( 2^{(1+2+3\cdots +n-1)})^{(1/n)}=(2^{[n(n-1)/2]})^{(1/n)}=2^{((n-1)/2)}](http://learnhub.com/images/equations/7e280840d9ced12526668b970426a9248c26fc15.png)
so
so we are done !!
Cauchy- Schwartz Inequality
If a,b,c and x,y,z be real numbers ( positive, negative or zero) then
Equality holds iff a:b:c::x:y:z
Example 3: if
find min value of 
use cauchy on
and 
then 


use cauchy on the numbers
and 
then 



squaring both sides of 1 and using 2 we get (x^4+y^4+z^4)<sup>4<=3[(x^6+y^6+z^6)</sup>2](x^4+y^4+z^4)](http://learnhub.com/images/equations/271e1065447ebd83e05ca9e7108ab1ae28fbc78a.png)
putting
and taking positive square root we get
Practice Problem 4: if a,b,c be positive numbers such that a+b+c=4 find minimum value of 
Practice Problem 5: Find the min value of 2x+y if xy=8 and x,y are positive numbers
Dear Riyana, this is a short lesson to revise some of the important concepts of Inequalities. In the very near future we will come up with lessons, exclusively on Inequalities, that will focus right from basics to advanced concepts.
re sureshbala this lesson is pretty good for cat aspirants but useless for gre test takers