deepa mittal said – Thu, 03 Sep 2009 05:43:25 -0000 ( Link )
1. At a certain time in a deer park, the number of heads and the number of legs of deer and human visitors were counted and it was found there were 39 heads & 132 legs. Find the number of deer and human visitors in the park.
Ans: No. of deers = 27 and No. of humans = 12
Solution:
Let the no. of deers be x And no. of humans be y
x + y = 39 — (1)
4 x + 2 y = 132 —- (2)
Multiply (1) and (2) On solving, we get … x = 27 and y= 12 No. of deers = 27 and No. of humans = 12
2. Find the sum of all 3 digit numbers which leave remainder 3 when divided by 5.
Ans: 99090
Solution : 103, 108……….998 a + (n-1)d = 998 103 + (n-1)5 = 998 n = 180
Let x be the sum of 180 terms
x = 180 + [(103 + 998)/2]
= 90×1101
= 99090
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deepa mittal said – Thu, 29 Oct 2009 04:48:00 -0000 ( Flag Edit Link )
Dear Sahil
You can post your problem here and we will try and solve the same.